A cyclist travels 15 km in 45 minutes. Calculate her average speed in m/s. Answer: ( 15 , km = 15000 , m ), ( 45 , min = 2700 , s ). ( v = 15000/2700 \approx 5.56 , m/s )
. Understanding the "why" behind the math prevents "brain freeze" during the exam.
| Concept | Formula | |---------|---------| | Average speed | (v = \fracst) | | Acceleration | (a = \frac\Delta v\Delta t) | | Uniform motion | (x = x_0 + vt) | | Accelerated motion | (v = v_0 + at,\quad x = x_0 + v_0 t + \frac12 a t^2) | | Newton’s 2nd law | (F = ma) | | Weight | (F_g = mg) | | Friction | (F_tr = \mu F_N) | | Work | (W = F \Delta x) | | Kinetic energy | (E_k = \frac12 m v^2) | | Potential energy | (E_p = m g h) | | Power | (P = \fracWt = F v) | | Pressure | (p = F/A) | | Hydrostatic pressure | (p = \rho g h) |
A cyclist travels 15 km in 45 minutes. Calculate her average speed in m/s. Answer: ( 15 , km = 15000 , m ), ( 45 , min = 2700 , s ). ( v = 15000/2700 \approx 5.56 , m/s )
. Understanding the "why" behind the math prevents "brain freeze" during the exam. fizika 1 letnik gimnazije test
| Concept | Formula | |---------|---------| | Average speed | (v = \fracst) | | Acceleration | (a = \frac\Delta v\Delta t) | | Uniform motion | (x = x_0 + vt) | | Accelerated motion | (v = v_0 + at,\quad x = x_0 + v_0 t + \frac12 a t^2) | | Newton’s 2nd law | (F = ma) | | Weight | (F_g = mg) | | Friction | (F_tr = \mu F_N) | | Work | (W = F \Delta x) | | Kinetic energy | (E_k = \frac12 m v^2) | | Potential energy | (E_p = m g h) | | Power | (P = \fracWt = F v) | | Pressure | (p = F/A) | | Hydrostatic pressure | (p = \rho g h) | A cyclist travels 15 km in 45 minutes